(22m^2)+(-m^2)=0

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Solution for (22m^2)+(-m^2)=0 equation: 



(22m^2)+(-m^2)=0

We add all the numbers together, and all the variables

22m^2+(-m^2)=0

We get rid of parentheses

22m^2-m^2=0

We add all the numbers together, and all the variables

21m^2=0

a = 21; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·21·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{42}=0$

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